- Home
- Standard 11
- Physics
1.Units, Dimensions and Measurement
medium
Which of the following is dimensional formula for viscosity?
A$[ML^{-1}T^{-2}]$
B$[MLT^{-1}]$
C$[ML^{-1}T^{-1}]$
D$[ML^{-2}T^{-2}]$
Solution
$\eta = \frac{Fr}{Av}$
$\eta=\frac{[M^1L^1T^{-2}][M^0L^1T^0]}{ [M^0L^2T^0] [M^0L^1T^{-1}]} = [M^1L^{-1}T^{-1}]$
$\eta=\frac{[M^1L^1T^{-2}][M^0L^1T^0]}{ [M^0L^2T^0] [M^0L^1T^{-1}]} = [M^1L^{-1}T^{-1}]$
Standard 11
Physics
