1.Units, Dimensions and Measurement
medium

Dimensions of kinetic energy are

A$M{L^2}{T^{ - 2}}$
B${M^2}L{T^{ - 1}}$
C$M{L^2}{T^{ - 1}}$
D$M{L^3}{T^{ - 1}}$

Solution

(a) Kinetic energy = $\frac{1}{2}m{v^2} = M{[L{T^{ – 1}}]^2} = [M{L^2}{T^{ – 2}}]$
Standard 11
Physics

Similar Questions

easy
(AIPMT-1994) (AIPMT-1990)

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