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Standard 11
Physics
English
Gujarati
Hindi
1.Units, Dimensions and Measurement
medium
Dimensions of kinetic energy are
A
$M{L^2}{T^{ - 2}}$
B
${M^2}L{T^{ - 1}}$
C
$M{L^2}{T^{ - 1}}$
D
$M{L^3}{T^{ - 1}}$
Solution
(a) Kinetic energy = $\frac{1}{2}m{v^2} = M{[L{T^{ – 1}}]^2} = [M{L^2}{T^{ – 2}}]$
Standard 11
Physics
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