Gujarati
Hindi
4-1.Newton's Laws of Motion
medium

Displacement of a particle of mass $2\, kg$ moving in a straight line varies with time as $s  = (2t^3 + 2)\, m$. Impulse of the force acting on the particle over a time interval between $t = 0$ and $t = 1\, s$ is .......... $N-s$

A

$10$

B

$12$

C

$8$

D

$6$

Solution

$\mathrm{v} =\frac{\mathrm{ds}}{\mathrm{dt}}=6 \mathrm{t}^{2} $

$\text { Impulse } =\Delta \mathrm{P}=\mathrm{m}\left(\mathrm{v}_{\mathrm{f}}-\mathrm{v}_{\mathrm{i}}\right)=2(6 \times 1-0)=12 \mathrm{N}-\mathrm{s}$

Standard 11
Physics

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