Divide Rs. 2602 between X and Y, so that the | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Let the first part be Rs. a Second part Rs. $(2602- a )$ According to question:

Amount after 7 years $=$ Amount after 9 years

$\Rightarrow a\lef

Vedclass · Accepted Answer

$Rs. 1352$, $Rs. 1250$

Vedclass · Answer

Let the first part be Rs. a Second part Rs. $(2602- a )$ According to question:

Amount after 7 years $=$ Amount after 9 years

$\Rightarrow a\left(1+\frac{r}{100}ight)^{7}=(2602-a)\left(1+\frac{r}{100}ight)^{9}$

$\Rightarrow \frac{ a }{(2602- a )}=\left(1+\frac{4}{100}ight)^{2}$

$\Rightarrow \frac{a}{(2602-a)}=\frac{26}{25} 	imes \frac{26}{25}=\frac{676}{625}$

$\Rightarrow 625 a=676(2602-a)$

$\Rightarrow \quad a=\frac{676 	imes 2602}{1301}= Rs .1352$

Second part $= Rs .(2602- a )= Rs .1250$

Divide $Rs. 2602$ between $X$ and $Y$, so that the amount of $X$ after $7 \,yr$ is equal to the amount of $Y$ after $9 \,yr$, the interest being compounded at $4 \%$ pa.

Similar Questions

What will be the compound interest (In ₹) on a sum of ₹ $50000$ after $4$ years at the rate of $10 \%$ per annum?

The difference between simple and compound interest on sum of $10000$ is $64$ for $2$ years. Find the rate of interest.

₹ $6,100$ was partly invested in Scheme $A$ at $10 \%$ p.a. compound interest (compounded annually) for $2$ years and partly in Scheme $B$ at $10 \%$ p.a. simple interest for $4$ years. Both the schemes pay equal interests. How much was invested (In ₹) in Scheme $A$?

The production of a factory grows at a $8 \%$ $p.a.$ What will be its production (In $lakh tonnes$) for the year $2010$ , if its production in $2008$ was $70$ lakh tonnes?

Rohit invested some amount at the rate of $6$ per cent pa and at the end of $3$ years he got ₹ $8730$ simple interest. How much compound interest (in ₹) he will get on same amount and same rate of interest after $2$ years.