Draw a graph for variation of potential $\mathrm{V}$ with distance $\mathrm{r}$ for a point charge $\mathrm{Q}$.
Electrostatic potential of a point charge $\mathrm{V}=\frac{k \mathrm{Q}}{r}$ and electric field $\mathrm{E}=\frac{k \mathrm{Q}}{r^{2}}$ here, $k \mathrm{Q}$ is constant $\therefore \mathrm{V} \propto \frac{1}{r}$ and $\mathrm{E} \propto \frac{1}{r^{2}}$
Equation of electrostatic potential $\mathrm{V}=\frac{k Q}{r}$ shows that if $\mathrm{Q}$ is positive then at all points electrostatic potential is positive and if $Q$ is negative then at all points electrostatic potential is negative.
The electric potential $V(x, y, z)$ for a planar charge distribution is given by:
$V\left( {x,y,z} \right) = \left\{ {\begin{array}{*{20}{c}}
{0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,for\,x\, < \, - d}\\
{ - {V_0}{{\left( {1 + \frac{x}{d}} \right)}^2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,for\, - \,d\, \le x < 0}\\
{ - {V_0}\left( {1 + 2\frac{x}{d}} \right)\,\,\,\,\,\,\,\,\,\,\,for\,0\, \le x < d}\\
{ - 3{V_0}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,for\,x\, > \,d}
\end{array}} \right.$
where $-V_0$ is the potential at the origin and $d$ is a distance. Graph of electric field as a function of position is given as
Two charged spheres of radii $10\, cm$ and $15\, cm$ are connected by a thin wire. No current will flow, if they have
The potential at a point, due to a positive charge of $100\,\mu C$ at a distance of $9\,m$, is
Calculate potential on the axis of a disc of radius $R$ due to a charge $Q$ uniformly distributed on its surface.
Four charges of $1\ \mu C, 2\ \mu C, 3\ \mu C,$ and $- 6\ \mu C$ are placed one at each corner of the square of side $1\,m$. The square lies in the $x-y$ plane with its centre at the origin.