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4. Linear Equations in Two Variables
medium
Draw the graph of each of the following linear equations in two varlables
$4 x-3 y=12$
Option A
Option B
Option C
Option D
Solution
$4 x-3 y=12$
$\therefore 4 x-12=3 y$
$\therefore y=\frac{4 x-12}{3}$
For $x=0,$ we get
$y=\frac{4(0)-12}{3}=\frac{-12}{3}=-4 ;$ i.e., $y=-4$
For $x=3,$ we get
$y=\frac{4[3]-12}{3}=\frac{0}{3}=0$ i.e., $y=0$
For $x=6,$ we get
$y=\frac{4(6)-12}{3}=\frac{12}{3}=4$ i.e., $y=4$
We can represent these solutions in the tabular form as below
$\begin{array}{|c|c|c|c|} \hline x & 0 & 3 & 6 \\ \hline y & -4 & 0 & 4 \\ \hline \end{array}$
Standard 9
Mathematics
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