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4. Linear Equations in Two Variables
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નીચેનાં સમીકરણોના આલેખ દોરો
$4 x-3 y=12$
Option A
Option B
Option C
Option D
Solution
$4 x-3 y=12$
$\therefore 4 x-12=3 y$
$\therefore y=\frac{4 x-12}{3}$
$x=0,$ માટે
$y=\frac{4(0)-12}{3}=\frac{-12}{3}=-4$
$x=3,$ માટે,
$y=\frac{4(3)-12}{3}=\frac{0}{3}=0$
$x=6,$ માટે,
$y=\frac{4(6)-12}{3}=\frac{12}{3}=4$ i.e., $y=4$
$\begin{array}{|c|c|c|c|} \hline x & 0 & 3 & 6 \\ \hline y & -4 & 0 & 4 \\ \hline \end{array}$
Standard 9
Mathematics
