Due to a small magnet intensity at a distance $x$ in the end on position is $9$ $Gauss$. What will be the intensity at a distance $\frac{x}{2}$ on broad side on position..... $Gauss$
$9$
$4$
$36$
$4.5$
In which direction does a free hanging magnet get stabilized ? Explain.
Two small bar magnets are placed in a line with like poles facing each other at a certain distance $d$ apart. If the length of each magnet is negligible as compared to $ d,$ the force between them will be inversely proportional to
The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of $20 \mathrm{~cm}$ from its center is $1.5 \times 10^{-5} \ \mathrm{Tm}$. The magnetic moment of the dipole is___________ $\mathrm{Am}^2$. (Given : $\frac{\mu_0}{4 \pi}=10^{-7} \ \mathrm{TmA}^{-1}$ )
A bar magnet of length $'l'$ and magnetic dipole moment $'M'$ is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be
The distance of two points on the axis of a magnet from its centre is $10 \,cm$ and $20 \,cm$ respectively. The ratio of magnetic intensity at these points is $12.5 : 1. $ The length of the magnet will be......$cm$