Gujarati
Hindi
11.Thermodynamics
normal

During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature. The ratio $C_P / C_V$ for the gas is

A

$1.5$

B

$1.33$

C

$2$

D

$1.67$

Solution

$P \propto T^{3}$

$\mathbf{P T}^{-3}=\mathrm{cont}$

$\because P^{1-\gamma} T^{\gamma}=$ cont

$\frac{\gamma}{1-\gamma}=-3 \Rightarrow \gamma=\frac{3}{2}$

Standard 11
Physics

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