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7.Gravitation
medium
Earth is revolving around the sun if the distance of the Earth from the Sun is reduced to $\frac{1}{4}^{th}$ of the present distance then the present day length reduced by
A
$\frac{1}{4}$
B
$\frac{1}{2}$
C
$\frac{1}{8}$
D
$\frac{1}{6}$
Solution
(c)$\frac{{{T_2}}}{{{T_1}}} = {\left( {\frac{{{r_2}}}{{{r_1}}}} \right)^{3/2}} = {\left( {\frac{1}{4}} \right)^{3/2}} = \frac{1}{8}$
Standard 11
Physics
Similar Questions
Match List$-I$ With List$-II$
$(a)$ Gravitational constant $(G)$ | $(i)$ $\left[ L ^{2} T ^{-2}\right]$ |
$(b)$ Gravitational potential energy | $(ii)$ $\left[ M ^{-1} L ^{3} T ^{-2}\right]$ |
$(c)$ Gravitational potential | $(iii)$ $\left[ LT ^{-2}\right]$ |
$(d)$ Gravitational intensity | $(iv)$ $\left[ ML ^{2} T ^{-2}\right]$ |
Choose the correct answer from the options given below: