Electrostatic potential energy of given system will be
Electrostatic potential energy of given system will be
- A
$\frac{{k{Q^2}}}{a} \times 10$
- B
$24\frac{{k{Q^2}}}{a}$
- C
$\frac{{k{Q^2}}}{a}\left( {24 + \frac{{11}}{{\sqrt 2 }}} \right)$
- D
$12\frac{{k{Q^2}}}{a}$
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