Electrostatic potential energy of given system will be

814-633

  • A

    $\frac{{k{Q^2}}}{a} \times 10$

  • B

    $24\frac{{k{Q^2}}}{a}$

  • C

    $\frac{{k{Q^2}}}{a}\left( {24 + \frac{{11}}{{\sqrt 2 }}} \right)$

  • D

    $12\frac{{k{Q^2}}}{a}$

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