2. Electric Potential and Capacitance
medium

There is an electric field $E$ in $X$-direction. If the work done on moving a charge $0.2\,C$ through a distance of $2\,m$ along a line making an angle $60^\circ $ with the $X$-axis is $4.0\;J$, what is the value of $E$........ $N/C$

A

$\sqrt 3 $

B

$4$

C

$5$

D

$20$

(AIPMT-1995)

Solution

(d) $W = qV = qE × d$

$4 = 0.2× E ×​ (2 cos $$60^\circ $)

$= 0.2 E ×​ (2 ×​ 0.5)$

$E = \frac{4}{{0.2}} = 20\,N{C^{ – 1}}$

Standard 12
Physics

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