Energy of photon whose frequency is ${10^{12}}MHz,$ will be
$4.14 \times {10^3}keV$
$4.14 \times {10^2}eV$
$4.14 \times {10^3}MeV$
$4.14 \times {10^3}eV$
The momentum of a photon of energy $1\,\, MeV$ in $kg \,\,m/s$ will be
A photon in motion has a mass
The velocity of photon is proportional to (where $v$ is frequency)
The light of two different frequencies whose photons have energies $3.8 \,eV$ and $1.4 \,eV$ respectively, illuminate a metallic surface whose work function is $0.6 \,eV$ successively. The ratio of maximum speeds of emitted electrons for the two frequencies respectivly will be