Gujarati
11.Dual Nature of Radiation and matter
easy

${10^{12}}MHz$ आवृत्ति के फोटॉन की ऊर्जा होगी

A

$4.14 \times {10^3}keV$

B

$4.14 \times {10^2}eV$

C

$4.14 \times {10^3}MeV$

D

$4.14 \times {10^3}eV$

Solution

$E(eV) = \frac{{h\nu }}{e} = \frac{{6.0 \times {{10}^{ – 34}} \times {{10}^{12}} \times {{10}^6}}}{{1.6 \times {{10}^{ – 19}}}}$$ = 4.14 \times {10^3}eV$

Standard 12
Physics

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