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11.Dual Nature of Radiation and matter
easy
${10^{12}}MHz$ आवृत्ति के फोटॉन की ऊर्जा होगी
A
$4.14 \times {10^3}keV$
B
$4.14 \times {10^2}eV$
C
$4.14 \times {10^3}MeV$
D
$4.14 \times {10^3}eV$
Solution
$E(eV) = \frac{{h\nu }}{e} = \frac{{6.0 \times {{10}^{ – 34}} \times {{10}^{12}} \times {{10}^6}}}{{1.6 \times {{10}^{ – 19}}}}$$ = 4.14 \times {10^3}eV$
Standard 12
Physics