Equation of the normal to the hyperbola $\frac{{{x^2}}}{{25}} - \frac{{{y^2}}}{{16}} = 1$ perpendicular to the line $2x + y = 1$ is
Equation of the normal to the hyperbola $\frac{{{x^2}}}{{25}} - \frac{{{y^2}}}{{16}} = 1$ perpendicular to the line $2x + y = 1$ is
- A
$\sqrt {21} \left( {x - 2y} \right) = 41$
- B
$x - 2y =1$
- C
$\sqrt {41} \left( {x - 2y} \right) = 41$
- D
$\sqrt {21} \left( {x - 2y} \right) = 21$
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- [AIEEE 2005]