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2. Polynomials
medium
Evaluate the following products without multiplying directly : $95 \times 96$
A
$9126$
B
$9230$
C
$9120$
D
$9100$
Solution
We have $95 \times 96=(100-5)(100-4)$
$=(100)^{2}+[(-5)+(-4)] \times 100+[(-5) \times(-4)]$
$\left[\right.$ Using $\left.(x+a)(x+b)=x^{2}+(a+b) x+a b\right]$
$=10000+[-9] \times 100+20=10000+(-900)+20$
$=9120$
Standard 9
Mathematics
