2. Polynomials
medium

सीधे गुणा किए बिना निम्नलिखित गुणनफलों के मान ज्ञात कीजिए

$95 \times 96$

A

$9126$

B

$9230$

C

$9120$

D

$9100$

Solution

We have $95 \times 96=(100-5)(100-4)$

$=(100)^{2}+[(-5)+(-4)] \times 100+[(-5) \times(-4)]$

$\left[\right.$ Using $\left.(x+a)(x+b)=x^{2}+(a+b) x+a b\right]$

$=10000+[-9] \times 100+20=10000+(-900)+20$

$=9120$

Standard 9
Mathematics

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