Explain the following :
$(1)$ Gallium has higher ionisation enthalpy than aluminum.
$(2)$ Boron does not exist as $B^{3+}$ ion.
The ionization enthalpy value of $\mathrm{Ga}$ is higher than $\mathrm{Al}$ due to inability of $d$ - and $f$-electrons, which have screening effect, to compensate the increase in nuclear charge.
Boron has small size and sum of $\Delta_{i} \mathrm{H}_{1}+\Delta_{i} \mathrm{H}_{2}+\Delta_{i} \mathrm{H}_{3}$ is very high. Boron does not form $\mathrm{B}^{3+}$ ion therefore, give covalent compounds.
During the borax bead test with $CuSO _4$, a blue green colour of the bead was observed in oxidising flame due to the formation of
The number of $2-$ centre $-2-$ electron and $3-$ centre $-2-$ electron bonds in $B_2H_6$, respectively, are
How would you explain the lower atomic radius of $Ga$ as compared to $Al$ ?
The structure of diborane contains :-
The possible oxidation state of $Tl$ are