Explain the following :
$(1)$ Gallium has higher ionisation enthalpy than aluminum.
$(2)$ Boron does not exist as $B^{3+}$ ion.
The ionization enthalpy value of $\mathrm{Ga}$ is higher than $\mathrm{Al}$ due to inability of $d$ - and $f$-electrons, which have screening effect, to compensate the increase in nuclear charge.
Boron has small size and sum of $\Delta_{i} \mathrm{H}_{1}+\Delta_{i} \mathrm{H}_{2}+\Delta_{i} \mathrm{H}_{3}$ is very high. Boron does not form $\mathrm{B}^{3+}$ ion therefore, give covalent compounds.
${H_3}B{O_3} + {H_2}O_2 \to {H_2}O + 'X' {\xrightarrow{{NAOH}} }{'Y'}$
Which of the following statements is $/$ are Correct for $'Y'$
Compare $\pi - $ bond strength between $B$ and $N$ given in two compounds
$(I)$ $\begin{array}{*{20}{c}}
{{{\left( {C{H_3}} \right)}_3}Si - NB{H_2}}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Si{{(C{H_3})}_3}}
\end{array}$ $(II)$ $\begin{array}{*{20}{c}}
{{{\left( {C{H_3}} \right)}_3}C - NB{H_2}}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{(C{H_3})}_3}}
\end{array}$
Moissan boron is
Inorganic graphite is:
Given below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R$:
Assertion $A$ : The stability order of +$1$ oxidation state of $\mathrm{Ga}$, In and $\mathrm{Tl}$ is $\mathrm{Ga}<\mathrm{In}<\mathrm{Tl}$.
Reason $R$ : The inert pair effect stabilizes the lower oxidation state down the group.
In the light of the above statements, choose the correct answer from the options given below :