Factorise : 2 x^{2}+7 x+3

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2. Polynomials

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Factorise : $2 x^{2}+7 x+3$

Option A

Option B

Option C

Option D

Solution

$2 x^{2}+7 x+3$

Here, $a =2,\, b =7$ and $c =3$

$\therefore \quad l+ m =7$ and $lm =2 \times 3=6$ i.e. $1+6=7$ and $1 \times 6=6$

$ \therefore $ $l=1$ and $m =6$

We have $ 2 x ^{2}+7 x +3=2 x ^{2}+x +6 x +3 $

$= x (2 x +1)+3(2 x +1)=(2 x +1)( x +3) $

Thus, $\quad 2 x^{2}+7 x+3=(2 x+1)(x+3)$

Standard 9

Mathematics

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