- Home
- Standard 9
- Mathematics
2. Polynomials
easy
Use the Factor Theorem to determine whether $g(x)$ is a factor of $p(x)$ in each of the following cases : $p(x)=x^{3}-4 x^{2}+x+6$, $g(x)=x-3$.
Option A
Option B
Option C
Option D
Solution
We have $p ( x )= x ^{3}-4 x ^{2}+ x +6$ and $g ( x )= x -3$
$ \therefore p (3) =(3)^{3}-4(3)^{2}+(3)+6=27-4(9)+3+6$
$=27-36+3+6=0 $
since $g(x)=0$
$\therefore g ( x )$ is a factor of $p ( x )$.
Standard 9
Mathematics
