- Home
- Standard 9
- Mathematics
2. Polynomials
easy
Factorise : $2 x^{2}+y^{2}+8 z^{2}-2 \sqrt{2} x y+4 \sqrt{2} y z-8 x z$
Option A
Option B
Option C
Option D
Solution
$2 x ^{2}+ y ^{2}+8 z ^{2}-2 \sqrt{2} xy +4 \sqrt{2} yz -8 xz$
$=(-\sqrt{2} x )^{2}+( y )^{2}+(2 \sqrt{2} z )^{2}+2(-\sqrt{2} x )( y )+2(2 \sqrt{2} z )( y )+2(2 \sqrt{2} z )(-\sqrt{2} x )$
$\quad=(-\sqrt{2} x + y +2 \sqrt{2} z )^{2}=(-\sqrt{2} x + y +2 \sqrt{2} z )(-\sqrt{2} x + y +2 \sqrt{2} z )$
Standard 9
Mathematics
