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2. Polynomials
hard
निम्नलिखित के गुणनखंड कीजिए
$16 x^{2}+4 y^{2}+9 z^{2}-16 x y-12 y z+24 x z$
Option A
Option B
Option C
Option D
Solution
$16 x^{2}+4 y^{2}+9 z^{2}-16 x y-12 y z+24 x$
$=(4 x)^{2}+(-2 y)^{2}+(3 z)^{2}+2(4 x)(-2 y)+2(-2 y)(3 z)+2(3 z)(4 x)$
$=\{4 x+(-2 y)+3 z\}^{2}\left[\because a^{2}+b^{2}+c^{2}+2 a b+2 b c+2 c a=(a+b+c)^{2}\right]$
$=(4 x-2 y+3 z)^{2}$
$=(4 x-2 y+3 z)(4 x-2 y+3 z)$
Standard 9
Mathematics