Figure shows tracks of three charged particles in a uniform electrostatic field. Give the signs of the three charges. Which particle has the highest charge to mass ratio?
Opposite charges attract each other and same charges repel each other. It can be observed that particles $1$ and $2$ both move towards the positively charged plate and repel away from the negatively charged plate.
Hence, these two particles are negatively charged. It can also be observed that particle $3$ moves towards the negatively charged plate and repels away from the positively charged plate. Hence, particle $3$ is positively charged.
The charge to mass ratio $(emf)$ is directly proportional to the displacement or amount of deflection for a given velocity. since the deflection of particle $3$ is the maximum, it has the highest charge to mass ratio.
A particle of mass $m$ and charge $q$ is thrown in a region where uniform gravitational field and electric field are present. The path of particle
An electron is rotating around an infinite positive linear charge in a circle of radius $0.1 \,m$, if the linear charge density is $1 \,\mu C / m$, then the velocity of electron in $m / s$ will be ...... $\times 10^7$
A particle of mass $m$ and charge $(-q)$ enters the region between the two charged plates initially moving along $x$ -axis with speed $v_{x}=2.0 \times 10^{6} \;m\, s ^{-1} .$ If $E$ between the plates separated by $0.5 \;cm$ is $9.1 \times 10^{2} \;N / C ,$ where will the electron strike the upper plate in $cm$?
$\left(|e|=1.6 \times 10^{-19} \;C , m_{e}=9.1 \times 10^{-31}\; kg .\right)$
An electron falls through a distance of $1.5\, cm$ in a uniform electric field of magnitude $2.0\times10^4\, N/C$ as shown in the figure. The time taken by electron to fall through this distance is ($m_e = 9.1\times10^{-31}\,kg$, Neglect gravity)
Under the influence of the Coulomb field of charge $+Q$, a charge $-q$ is moving around it in an elliptical orbit. Find out the correct statement$(s)$.