1. Electric Charges and Fields
easy

An electron is rotating around an infinite positive linear charge in a circle of radius $0.1 \,m$, if the linear charge density is $1 \,\mu C / m$, then the velocity of electron in $m / s$ will be ...... $\times 10^7$

A

$0.562$

B

$5.62$

C

$562$

D

$0.0562$

Solution

(b)

$\frac{m v^2}{r}=q E$

$\frac{m v^2}{r}=e \cdot \frac{\lambda}{2 \pi \varepsilon_0 r}$

$v=5.62 \times 10^7 \,m / s$

Standard 12
Physics

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