Figure below shows a body of mass M moving with uniform speed on a circular path of radius, R . chan

English

Gujarati

Hindi

3-2.Motion in Plane

medium

Figure below shows a body of mass $M$ moving with the uniform speed on a circular path of radius, $R$. What is the change in acceleration in going from ${P_1}$ to ${P_2}$

AZero

B${v^2}/2R$

C$2{v^2}/R$

D$\frac{{{v^2}}}{R} \times \sqrt 2 $

Solution

(d) $\Delta a = 2a\sin \left( {\frac{\theta }{2}} \right)$= $2a \times \sin 45^\circ $$ = \sqrt 2 a = \sqrt 2 \frac{{{v^2}}}{R}$

Standard 11

Physics

Share

Similar Questions

The second's hand of a watch has $6\, cm$ length. The speed of its tip and magnitude of difference in velocities of its at any two perpendicular positions will be respectively

medium

If the body is moving in a circle of radius $ r$ with a constant speed $v$, its angular velocity is

easy

A particle is revolving in a circle of radius $2\ m$ with angular velocity $\omega = t^2 -4t + 8\ rad/s$ . The time when speed of the particle becomes $8\ m/s$ is ……… $\sec$

medium

For a particle in uniform circular motion, the acceleration $\vec a$ at a point $P(R,\theta)$ on the circle of radius $R$ is (Here $\theta$ is measured from the $x-$ axis)

medium

(AIEEE-2010)

The radius of circle the period of revolution initial position and sense of revolution are indicated in the figure.
$y-$projection of the radius vector of rotating particle $\mathrm{P}$ is

medium

(NEET-2019)