For a particle in uniform circular motion, acceleration vec a at a point P(R,θ) on circle of radius

English

Gujarati

Hindi

3-2.Motion in Plane

medium

For a particle in uniform circular motion, the acceleration $\vec a$ at a point $P(R,\theta)$ on the circle of radius $R$ is (Here $\theta$ is measured from the $x-$ axis)

A$\frac{{{V^2}}}{R}\widehat i + \frac{{{V^2}}}{R}\widehat j$

B$ - \frac{{{V^2}}}{R}\cos \theta \widehat i + \frac{{{V^2}}}{R}\sin \theta \widehat j$

C$ - \frac{{{V^2}}}{R}\sin \theta \widehat i + \frac{{{V^2}}}{R}\cos \theta \widehat j$

D$ - \frac{{{V^2}}}{R}\cos \theta \widehat i - \frac{{{V^2}}}{R}\sin \theta \widehat j$

(AIEEE-2010) (JEE MAIN-2022)

Solution

$\begin{array}{l}
Clearly\,\vec a = {a_c}\cos \theta \left( { – \hat i} \right) + {a_c}\sin \theta \left( { – \hat j} \right)\\
= \frac{{ – {v^2}}}{R}\cos \theta \hat i – \frac{{{v^2}}}{R}\sin \theta \hat j
\end{array}$

Standard 11

Physics

A particle is moving on a circular path of radius $r$ with uniform velocity $v$. The change in velocity when the particle moves from $P$ to $Q$ is $(\angle POQ = 40^\circ )$

easy

car moves on a circular road. It describes equal angles about the centre in equal intervals of time. Which of the following statement about the velocity of the car is true

easy

A particle $B$ is moving in a circle of radius $a$ with a uniform speed $u$. $C$ is the centre of the circle and $AB$ is diameter. The angular velocity of $B$ about $A$ and $C$ are in the ratio

medium

A particle is revolving in a circle of radius $2\ m$ with angular velocity $\omega = t^2 -4t + 8\ rad/s$ . The time when speed of the particle becomes $8\ m/s$ is ……… $\sec$

medium

The second's hand of a watch has length $6\,\, cm$. Speed of end point and magnitude of difference of velocities at two perpendicular positions will be

medium

For a particle in uniform circular motion, the acceleration $\vec a$ at a point $P(R,\theta)$ on the circle of radius $R$ is (Here $\theta$ is measured from the $x-$ axis)

Solution

Similar Questions

A particle is moving on a circular path of radius $r$ with uniform velocity $v$. The change in velocity when the particle moves from $P$ to $Q$ is $(\angle POQ = 40^\circ )$

car moves on a circular road. It describes equal angles about the centre in equal intervals of time. Which of the following statement about the velocity of the car is true

A particle $B$ is moving in a circle of radius $a$ with a uniform speed $u$. $C$ is the centre of the circle and $AB$ is diameter. The angular velocity of $B$ about $A$ and $C$ are in the ratio

A particle is revolving in a circle of radius $2\ m$ with angular velocity $\omega = t^2 -4t + 8\ rad/s$ . The time when speed of the particle becomes $8\ m/s$ is ……… $\sec$

The second's hand of a watch has length $6\,\, cm$. Speed of end point and magnitude of difference of velocities at two perpendicular positions will be

Start a Free Trial Now