Figure shows a small wheel fixed coaxially on | vedclass

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Question

Linear displacement $(S)$ = Radius $(r)$ $&times;$ Angular displacement $(q)$

 $	herefore S \propto r$ (if $	heta  = $ constant)

&nb

Vedclass · Accepted Answer

$y = 2x$

Vedclass · Answer

Linear displacement $(S)$ = Radius $(r)$ $&times;$ Angular displacement $(q)$

 $	herefore S \propto r$ (if $	heta  = $ constant)

 $\frac{{{m{Distance\ travelled\ by\ mass }}\ A\,(x)}}{{{m{Distance\ travelled\ by\ mass }}\ B\,(y)}}$

= $\frac{{{m{Radius\ of\ pulley\ concerned\  with\ mass }}\ A\,(r)}}{{{m{Radius\ of\ pulley\ concerned\ with\ mass }}\ B\,(2r)}}$ $ = \frac{1}{2}$   

 $y = 2x$.

Figure shows a small wheel fixed coaxially on a bigger one of double the radius. The system rotates about the common axis. The strings supporting $A$ and $B$ do not slip on the wheels. If $x$ and $y$ be the distances travelled by $A$ and $B$ in the same time interval, then

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