Gujarati
Hindi
1. Electric Charges and Fields
medium

Figure shows four charges $q_1, q_2, q_3$ and $q_4$ fixed in space. Then the total flux of electric field through a closed surface $S$, due to all charges $q_1, q_2, q_3$ and $q_4$ is

A

not equal to the total flux through to charges $q_3$ and $q_4$

B

equal to the total flux through $S$ due to charges $q_3$ and $q_4$

C

zero if $q_1 + q_2 = q_3 + q_4$

D

twice the total flux through $S$ due to charges $q_3$ and $q_4$ if $q_1 + q_2 = q_3 + q_4$

Solution

From Gauss's law, the flux, $\phi=\frac{Q_{en}}{\epsilon_{0}}$ where $Q_{e n}$ be the charge enclosed by the surface.

Here, $Q_{e n}=q_{3}+q_{4}$

So, net flux through the closed surface, $\phi=\frac{q_{3}+q_{4}}{\epsilon_{0}}$

Thus, it is due to only charges $q_{3}$ and $q_{4}$ which are inside the surface.

Standard 12
Physics

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