Gujarati
Hindi
12.Kinetic Theory of Gases
normal

Figure shows the volume versus temperature graph for the same mass of a gas (assumed ideal) corresponding to two different pressures $P_1$ and $P_2$. Then,

A

$P_1\,\, > P_2$

B

$P_1\,\, < P_2$

C

$P_1\,\, = P_2$

D

The information is insufficient

Solution

Since the graph is a straight line, so, $V = mT$  where $m$  is the slope. $= (nRT)/P$  [From equation of state] or $m \propto (1/P)$  or

$\Rightarrow m_2\,\,>\,\,m_1$

$\therefore P_1\,\,>\,\,P_2$

Standard 11
Physics

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