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12.Kinetic Theory of Gases
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Figure shows the volume versus temperature graph for the same mass of a gas (assumed ideal) corresponding to two different pressures $P_1$ and $P_2$. Then,

A
$P_1\,\, > P_2$
B
$P_1\,\, < P_2$
C
$P_1\,\, = P_2$
D
The information is insufficient
Solution
Since the graph is a straight line, so, $V = mT$ where $m$ is the slope. $= (nRT)/P$ [From equation of state] or $m \propto (1/P)$ or
$\Rightarrow m_2\,\,>\,\,m_1$
$\therefore P_1\,\,>\,\,P_2$
Standard 11
Physics