Average kinetic energy of a gas molecule at 27,^oC is 6.21 × 10^{-21},J . Its average kinetic energ

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12.Kinetic Theory of Gases

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The average kinetic energy of a gas molecule at $27\,^oC$ is $6.21 \times 10^{-21}\,J$ . Its average kinetic energy at $227\,^oC$ will be

A

$52.2\times 10^{-21}\,J$

B

$5.22\times 10^{-21}\,J$

C

$10.35\times 10^{-21}\,J$

D

$11.35\times 10^{-21}\,J$

Solution

$\mathrm{E} \propto \mathrm{T}$

$\frac{E_{1}}{E_{2}}=\frac{T_{1}}{T_{2}}$

$\frac{6.21 \times 10^{-21}}{\mathrm{E}_{2}}=\frac{300}{500}$

$\mathrm{E}_{2}=10.35 \times 10^{-21} \mathrm{\,J}$

Standard 11

Physics

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