Figure shows two cases. In first case a spring (spring constant K ) is pulled by two equal and oppos

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4-1.Newton's Laws of Motion

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Figure shows two cases. In first case a spring (spring constant $K$ ) is pulled by two equal and opposite forces $F$ at both ends and in second case is pulled by a force $F$ at one end. Extensions $(x)$ in the springs will be

AIn both cases $x=\frac{2 F}{K}$

BIn both cases $x=\frac{F}{K}$

CIn first case $x=\frac{2 F}{K}$, in second case $x=\frac{F}{K}$

DIn first case $x=\frac{F}{K}$, in second case $x=\frac{2 F}{K}$

Solution

(b)
Figure $(2)$ is $F.B.D.$ of figure $(1)$ at equilibrium $F=K x$
$x=F / K$

Standard 11

Physics

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