Two masses of 10 ,kg and 20 ,kg respectivety are connected by a massless spring as shown in fig. A f

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4-1.Newton's Laws of Motion

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Two masses of $10 \,kg$ and $20 \,kg$ respectivety are connected by a massless spring as shown in fig. A force of $200 \,N$ acts on the $20 \,kg$ mass At the instant shown the $10 \,kg$ mass has acceleration $12 \,m / s ^2$ towards right. The acceleration of $20 \,kg$ mass at this instant is ........ $m / s ^2$

A$12$

B$4$

C$10$

DZero

Solution

(b)
$F_s$ is spring force
$F_s=10 \times 12=120\,N$
for $20 \,kg$ block
$200-120=20 a$
$a=\frac{80}{20}=4 \,m / s ^2$

Standard 11

Physics

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