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4-1.Newton's Laws of Motion
medium
Figures $(a), (b), (c)$ and $(d)$ show variation of force with time.
The impulse is highest in figure.

A
Fig $(c)$
B
Fig $(b)$
C
Fig $(a)$
D
Fig $(d)$
(JEE MAIN-2023)
Solution
Impulse $=$ Area under $F=t$ curve
$(a)$ $\frac{1}{2} \times 1 \times 0.5=\frac{1}{4}\,N . s$
$(b)$ $0.5 \times 2=1$ N.s (maximum)
$(c)$ $\frac{1}{2} \times 1 \times 0.75=\frac{3}{8} N . s$
$(d)$ $\frac{1}{2} \times 2 \times 0.5=\frac{1}{2} N . s$
Standard 11
Physics
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