4-1.Newton's Laws of Motion
medium

Figures $(a), (b), (c)$ and $(d)$ show variation of force with time.

The impulse is highest in figure.

A

Fig $(c)$

B

Fig $(b)$

C

Fig $(a)$

D

Fig $(d)$

(JEE MAIN-2023)

Solution

Impulse $=$ Area under $F=t$ curve

$(a)$ $\frac{1}{2} \times 1 \times 0.5=\frac{1}{4}\,N . s$

$(b)$ $0.5 \times 2=1$ N.s (maximum)

$(c)$ $\frac{1}{2} \times 1 \times 0.75=\frac{3}{8} N . s$

$(d)$ $\frac{1}{2} \times 2 \times 0.5=\frac{1}{2} N . s$

Standard 11
Physics

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