Fill in the blank : Force constant of spring is $0.5\, Nm^{-1}$. The force necessary to increase the length of $10 \,cm$ of spring will be ..........

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$\mathrm{F}=\mathrm{k} \Delta x$ $=0.5 \times 10 \times 10^{-2}$ $=0.05 \mathrm{~N}$

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