Suppose the vectors $x_{1}, x_{2}$ and $x_{3}$ are the solutions of the system of linear equations, $Ax = b$ when the vector $b$ on the right side is equal to $b _{1}, b _{2}$ and $b _{3}$ respectively. If $x =\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right], x _{2}=\left[\begin{array}{l}0 \\ 2 \\ 1\end{array}\right], x _{3}=\left[\begin{array}{l}0 \\ 0 \\ 1\end{array}\right], b _{1}=\left[\begin{array}{l}1 \\ 0 \\ 0\end{array}\right]$ $b _{2}=\left[\begin{array}{l}0 \\ 2 \\ 0\end{array}\right]$ and $b _{3}=\left[\begin{array}{l}0 \\ 0 \\ 2\end{array}\right],$ then the determinant of $A$ is equal to

Let $A=\left[\begin{array}{ll}0 & 1 \\ 0 & 0\end{array}\right],$ show that $(a \mathrm{I}+b \mathrm{A})^{n}=a^{n} \mathrm{I}+n a^{n-1} b \mathrm{A},$ where $\mathrm{I}$ is the identity matrix of order $2$ and $n \in \mathrm{N}$.

If $A$ and $B$ are $3 \times 3$matrices such that $AB = A$ and $BA = B$, then

If $A = \left[ {\begin{array}{*{20}{c}}1&0&1\\0&1&1\\1&0&0\end{array}} \right]$, then $A$ is

Let matrix $A = \left[ {\begin{array}{*{20}{c}}
  1&2&3 \\ 
  0&5&4 \\ 
  0&3&2 
\end{array}} \right]$ and $A^3 -8A^2 + \alpha A + \beta I = O$ then ordered pair $(\alpha , \beta)$ is