Find p(0) , p(1) and p(2) for of following polynomials : p(x)=x^{3}

English

Gujarati

Hindi

2. Polynomials

easy

Find $p(0)$, $p(1)$ and $p(2)$ for of the following polynomials : $p(x)=x^{3}$

Option A

Option B

Option C

Option D

Solution

$p(x)=x^{3}$

$\because $ $p(x)=x^{3}=(x)^{3}$

$\therefore$ $p(0)=(0)^{3}=0$

$p(1)=(1)^{3}=1$

$p(2)=(2)^{3}=8$ $[\because \,\,2 \times 2 \times 2=8]$

Standard 9

Mathematics

Share

Similar Questions

Classify the following as linear, quadratic and cubic polynomials :

$(i)$ $1+x$

$(ii)$ $3 t$

$(iii)$ $r^{2}$

$(iv)$ $7 x^{3}$

medium

Without actually calculating the cubes, find the value of each of the following : $(28)^{3}+(-15)^{3}+(-13)^{3}$

medium

Divide $p(x)$ by $g(x)$, where $p(x) = x + 3x^2 -1$ and $g(x) = 1 + x$.

medium

Factorise $4 x^{2}+y^{2}+z^{2}-4 x y-2 y z+4 x z$.

medium

Verify whether the following are zeroes of the polynomial, indicated against them.

$p(x)=x^{2}, \,x=0$

easy