Find p(0), p(1), p(-2) for following polynomials: p(x)=10 x-4 x^{2}-3

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2. Polynomials

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Find $p(0), p(1), p(-2)$ for the following polynomials:

$p(x)=10 x-4 x^{2}-3$

Option A

Option B

Option C

Option D

Solution

$(i)$ We have $p(x)=10 x-4 x^{2}-3$

$\therefore \quad p(0)=10(0)-4(0)^{2}-3$

$=0-0-3=-3$

And, $\quad p(1)=10(1)-4(1)^{2}-3$

$=10-4-3=10-7=3$

And, $\quad P(-2)=10(-2)-4(-2)^{2}-3$

$=-20-4(4)-3=-20-16-3=-39$

Standard 9

Mathematics

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