Radian measures corresponding to following degree measures: -47^{circ} 30^{prime}

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3.Trigonometrical Ratios, Functions and Identities

easy

Find the radian measures corresponding to the following degree measures:

$-47^{\circ} 30^{\prime}$

$\frac{-19}{72} \pi$

Solution

$-47^{\circ} 30^{\prime}-47 \frac{1}{2}$

$=\frac{-95}{2}$ degree

since $180^{\circ}=\pi$ radian

$\frac{-95}{2}$ degree $=\frac{\pi}{180} \times\left(\frac{-95}{2}\right)$ radian $=\left(\frac{-19}{36 \times 2}\right) \pi$ radian $=\frac{-19}{72} \pi$ radian

$\therefore-47^{\circ} 30^{\prime}=\frac{-19}{72} \pi$ radian

Standard 11

Mathematics

If $x\sin 45^\circ {\cos ^2}60^\circ = \frac{{{{\tan }^2}60^\circ {\rm{cosec}}30^\circ }}{{\sec 45^\circ {{\cot }^2}30^\circ }},$ then $x = $

easy

If $\tan \theta = \frac{{20}}{{21}},$ cos$\theta$ will be

easy

Convert $40^{\circ} 20^{\prime}$ into radian measure.

easy

Find $\sin \frac{x}{2}, \cos \frac{x}{2}$ and $\tan \frac{x}{2}$ for $\sin x=\frac{1}{4}, x$ in quadrant $II$

hard

$\tan 1^\circ \tan 2^\circ \tan 3^\circ \tan 4^\circ ……..\tan 89^\circ = $

easy

Find the radian measures corresponding to the following degree measures: $-47^{\circ} 30^{\prime}$

Solution

Similar Questions

If $x\sin 45^\circ {\cos ^2}60^\circ = \frac{{{{\tan }^2}60^\circ {\rm{cosec}}30^\circ }}{{\sec 45^\circ {{\cot }^2}30^\circ }},$ then $x = $

If $\tan \theta = \frac{{20}}{{21}},$ cos$\theta$ will be

Convert $40^{\circ} 20^{\prime}$ into radian measure.

Find $\sin \frac{x}{2}, \cos \frac{x}{2}$ and $\tan \frac{x}{2}$ for $\sin x=\frac{1}{4}, x$ in quadrant $II$

$\tan 1^\circ \tan 2^\circ \tan 3^\circ \tan 4^\circ ……..\tan 89^\circ = $

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Find the radian measures corresponding to the following degree measures:

$-47^{\circ} 30^{\prime}$