3 and 4 .Determinants and Matrices
easy

પરિવર્તિત શ્રેણિક મેળવો :  $\left[\begin{array}{cc}1 & -1 \\ 2 & 3\end{array}\right]$

A

$\left[\begin{array}{cc}1 & 2 \\ -1 & 3\end{array}\right]$

B

$\left[\begin{array}{cc}1 & 2 \\ -1 & 3\end{array}\right]$

C

$\left[\begin{array}{cc}1 & 2 \\ -1 & 3\end{array}\right]$

D

$\left[\begin{array}{cc}1 & 2 \\ -1 & 3\end{array}\right]$

Solution

Let $A=\left[\begin{array}{ll}1 & -1 \\ 2 & 3\end{array}\right],$ then $A^{T}=\left[\begin{array}{cc}1 & 2 \\ -1 & 3\end{array}\right]$

Standard 12
Mathematics

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