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3 and 4 .Determinants and Matrices
easy
પરિવર્તિત શ્રેણિક મેળવો : $\left[\begin{array}{cc}1 & -1 \\ 2 & 3\end{array}\right]$
A
$\left[\begin{array}{cc}1 & 2 \\ -1 & 3\end{array}\right]$
B
$\left[\begin{array}{cc}1 & 2 \\ -1 & 3\end{array}\right]$
C
$\left[\begin{array}{cc}1 & 2 \\ -1 & 3\end{array}\right]$
D
$\left[\begin{array}{cc}1 & 2 \\ -1 & 3\end{array}\right]$
Solution
Let $A=\left[\begin{array}{ll}1 & -1 \\ 2 & 3\end{array}\right],$ then $A^{T}=\left[\begin{array}{cc}1 & 2 \\ -1 & 3\end{array}\right]$
Standard 12
Mathematics