3 and 4 .Determinants and Matrices
easy

Find the value of $x,\,y$ and $z$ from the following equation : $\left[\begin{array}{c}x+y+z \\ x+z \\ y+z\end{array}\right]=\left[\begin{array}{l}9 \\ 5 \\ 7\end{array}\right]$

A

$x=2$,  $y=4,$  $z=3$

B

$x=4$,  $y=4,$  $z=3$

C

$x=2$,  $y=2,$  $z=3$

D

$x=2$,  $y=4,$  $z=5$

Solution

$\left[\begin{array}{c}x+y+z \\ x+z \\ y+z\end{array}\right]=\left[\begin{array}{l}9 \\ 5 \\ 7\end{array}\right]$

As the two matrices are equal, their corresponding elements are also equal. Comparing the corresponding elements, we get:

$x+y+z=9$             ……….. $(1)$

$x+z=5$             ……….. $(2)$

$y+z=7$             ……….. $(3)$

From $(1)$ and $(2)$, we have :

$y+5=9 \Rightarrow y=4$

From $( 3 )$, we have :

$4+z=7 \Rightarrow z=3$

$\therefore $    $x+z=5 \Rightarrow x=2$

$\therefore $    $x=2$,  $y=4,$ and $z=3$

Standard 12
Mathematics

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