Value of cos left(-1710^{circ}right) .

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3.Trigonometrical Ratios, Functions and Identities

easy

Find the value of $\cos \left(-1710^{\circ}\right)$.

A

$0$

B

$0$

C

$0$

D

$0$

Solution

We know that values of cos $x$ repeats after an interval of $2 \pi$ or $360^{\circ} .$

Therefore, $\cos \left(-1710^{\circ}\right)=\cos \left(-1710^{\circ}+5 \times 360^{\circ}\right)$

$=\cos \left(-1710^{\circ}+1800^{\circ}\right)=\cos 90^{\circ}=0$

Standard 11

Mathematics

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