2. Polynomials
easy

Find the value of each of the following polynomials at the indicated value of variables

$p(x)=x^{2}+5 x-24$ at $x=3$

A

$3$

B

$0$

C

$5$

D

$9$

Solution

$p(x)=x^{2}+5 x-24$

Replacing $x$ by $3,$ we get

$p(3)=(3)^{2}+5(3)-24$

$=9+15-24=24-24=0$

Therefore, the value of $p(x)$ at $x=3$ is $0 .$

Standard 9
Mathematics

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