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2. Polynomials
easy
Find the value of each of the following polynomials at the indicated value of variables
$p(x)=x^{2}+5 x-24$ at $x=3$
A
$3$
B
$0$
C
$5$
D
$9$
Solution
$p(x)=x^{2}+5 x-24$
Replacing $x$ by $3,$ we get
$p(3)=(3)^{2}+5(3)-24$
$=9+15-24=24-24=0$
Therefore, the value of $p(x)$ at $x=3$ is $0 .$
Standard 9
Mathematics