Find the value of the polynomial $3 x^{3}-4 x^{2}+7 x-5,$ when $x=-3$
$160$
$143$
$-143$
$-160$
Let $p(x)=3 x^{2}-4 x^{2}+7 x-5$
Now, $p(-3)=3(-3)^{3}-4(-3)^{2}+7(-3)-5$
$=3(-27)-4(9)-21-5$
$=-81-36-21-5$
$=-143$
For polynomial $p(x)=x^{3}-3 x^{2}+8 x+12$, $p(-1)=\ldots \ldots \ldots$
Factorise the following quadratic polynomials by splitting the middle term
$x^{2}+2 x-143$
For the polynomial $p(x)=x^{2}-7 x+12$ $p(2)=\ldots \ldots . .$
Factorise $: 4 x^{2}+4 x y-3 y^{2}$
Factorise the following:
$16 x^{2}+4 y^{2}+9 z^{2}-16 x y-12 y z+24 x z$
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