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3.Trigonometrical Ratios, Functions and Identities
easy
Find the value of the trigonometric function $\sin 765^{\circ}$
A
$\frac{1}{\sqrt{2}}$
B
$\frac{1}{\sqrt{2}}$
C
$\frac{1}{\sqrt{2}}$
D
$\frac{1}{\sqrt{2}}$
Solution
It is known that the values of $\sin x$ repeat after an interval of $2 n$ or $360^{\circ} .$
$\therefore \sin 765^{\circ}=\sin \left(2 \times 360^{\circ}+45^{\circ}\right)$
$=\sin 45^{\circ}=\frac{1}{\sqrt{2}}$
Standard 11
Mathematics