Find the zeroes of the polynomial in each of the following:
$p(x)=x-4$
$1$
$2$
$3$
$4$
Solving the equation $p(x)=0,$ we get
$x-4=0,$ which give us $x=4$
So, $4$ is a zero of the polynomial $x-4$.
Factorise
$16 x^{2}+40 x y+25 y^{2}$
Write whether the statement are True or False. Justify your answer.
A polynomial cannot have more than one zero.
Factorise :
$2 x^{2}-7 x-15$
Verify whether the following are True or False:
$-3$ is a zero of $y^{2}+y-6.$
If $p(x)=x^{4}-2 x^{3}+3 x^{2}-a x+3 a-7$ is divided by $(x+1),$ then the remainder is $19 .$ Find the value of a. Also, find the remainder, when $p(x)$ is divided by $(x+2)$
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