Five balls marked a to e are suspended using separate threads. Pairs (b, c) and (d, e) show electros

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1. Electric Charges and Fields

normal

Five balls marked a to $e$ are suspended using separate threads. Pairs $(b, c)$ and $(d, e)$ show electrostatic repulsion while pairs $(a, b),(c, e)$ and $(a, e)$ show electrostatic attraction. The ball marked a must be

Negatively charged

Positively charged

Uncharged

Any of the above is possible

Solution

(c)

Draw the diagram of given situation

$b,c$ have same change (repulsion)

$d,e$ have same charge (repulsion)

$a, b$ have opposite charge (attraction)

$c,e$ have opposite charge (attraction)

$a,e$ have opposite charge (attraction)

calculating charge of ' $a$ '

let $a$ is positive

then

$b$ is negative

$c$ is negative

$d$ is negative

$e$ is negative

but $(a, e)$ attract not possible because of having same. Similarly if $a$ is negative then also $e$ will be negative. In both case attraction will not possible in $(a, e)$. Hence ' $a$ ' is. unchanged.

Standard 12

Physics

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normal

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normal

Five balls marked a to $e$ are suspended using separate threads. Pairs $(b, c)$ and $(d, e)$ show electrostatic repulsion while pairs $(a, b),(c, e)$ and $(a, e)$ show electrostatic attraction. The ball marked a must be

Solution

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