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Five balls numbered $1$ to $5$ are suspended using separate threads. Pairs $(1,2), (2,4)$ and $(4,1)$ show electrostatic attraction while pairs $(2,3)$ and $(4,5)$ show repulsion. Therefore ball $1$ must be
positively charged
made of metal
neutral
$B$ and $C$ both
Solution
It should be neutral because $2,$ and 4 show attraction means have opposite charge 2 too show attraction with 1 means 1 and 4 should have same charge but as they are showing attraction too then. 1 should be electricity neutral. Besides, it can be seen that ball 2 is positively charged then ball 4 is negatively charged because 2 and 4 show attraction. Now ball if ball 2 is $(+v e)$ charged then ball 3 is also $(+v e)$ charged because 2 and 3 also show repulsion and similarly ball 5 is $(-v e)$ charged because ball 4 and 5 show repulsion and we left with ball 1 and it never be $(+v e)$ by charged because ball 2 and 1 show attraction it means ball 1 is negatively charge but it is also not possible because ball 1 and 4 also show attraction and in the end we know that ball 1 is nor be positively or neither be negatively charge. It means be ball 1 have no charge so it must be neutral.