A parallel plate condenser with plate area $A$ and separation $d$ is filled with two dielectric materials as shown in the figure. The dielectric constants are $K_1$ and $K_2$ respectively. The capacitance will be
$\frac{{{\varepsilon _0}A}}{d}\left( {{K_1} + {K_2}} \right)$
$\frac{{{\varepsilon _0}A}}{d}\left( {\frac{{{K_1} + {K_2}}}{{{K_1}{K_2}}}} \right)$
$\frac{{2{\varepsilon _0}A}}{d}\left( {\frac{{{K_1} {K_2}}}{{{K_1}+{K_2}}}} \right)$
$\frac{{2{\varepsilon _0}A}}{d}\left( {\frac{{{K_1} + {K_2}}}{{{K_1}{K_2}}}} \right)$
Half of the space between parallel plate capacitor is filled with a medium of dielectric constant $K$ parallel to the plates . If initially the capacity is $C$, then the new capacity will be
Charge $q$ is uniformly distributed over a thin half ring of radius $R$. The electric field at the centre of the ring is
An electric dipole of dipole moment $\vec P$ is lying along a uniform electric field $\vec E$ . The work done in rotating the dipole by $90^o$ is
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