A parallel plate condenser with plate area $A$ and separation $d$ is filled with two dielectric materials as shown in the figure. The dielectric constants are $K_1$ and $K_2$ respectively. The capacitance will be
A parallel plate condenser with plate area $A$ and separation $d$ is filled with two dielectric materials as shown in the figure. The dielectric constants are $K_1$ and $K_2$ respectively. The capacitance will be
- A
$\frac{{{\varepsilon _0}A}}{d}\left( {{K_1} + {K_2}} \right)$
- B
$\frac{{{\varepsilon _0}A}}{d}\left( {\frac{{{K_1} + {K_2}}}{{{K_1}{K_2}}}} \right)$
- C
$\frac{{2{\varepsilon _0}A}}{d}\left( {\frac{{{K_1} {K_2}}}{{{K_1}+{K_2}}}} \right)$
- D
$\frac{{2{\varepsilon _0}A}}{d}\left( {\frac{{{K_1} + {K_2}}}{{{K_1}{K_2}}}} \right)$
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