For a body moving in a circular path, a condition for no skidding if $\mu $ is the coefficient of friction, is
$\frac{{m{v^2}}}{r} \le \mu mg$
$\frac{{m{v^2}}}{r} \ge \mu mg$
$\frac{v}{r} = \mu g$
$\frac{{m{v^2}}}{r} = \mu mg$
A particle moves in a circle of radius $25\, cm$ at two revolutions per second. The acceleration of the particle in $meter/second^2$ is
A conical pendulum is moving in a circle with angular velocity $\omega $ as shown. If tension in the string is $T$ , which of following equation are correct?
particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are $\vec a\, = \,(4\hat i + 3\hat j)\,\,m/{s^2}$ and $\vec P\, = \,(8\hat i\, - \,6\hat j)\,kg\, - \,m/s$ . The motion of the particle is
A particle is moving in a circle of radius $r$ having centre at $O$, with a constant speed $v$. The magnitude of change in velocity in moving from $A$ to $B$ is
A boy ties a stone of mass $100 \,g$ to the end of a $2$ $m$ long string and whirls it around in a horizontal plane. The string can withstand the maximum tension of $80 \,N$. If the maximum speed with which the stone can revolve is $\frac{ K }{\pi} rev$. / $min$. The value of $K$ is (Assume the string is massless and unstretchable)