For a projectile the ratio of maximum height reached to the square of flight time is

A projectile is fired at $30^{\circ}$ to the horizontal, The vertical component of its velocity is $80 \;ms ^{-1}$, Its time flight is $T$. What will be the velocity of projectile at $t =\frac{ T }{2}$?

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is  .......... $^o$

Find time of flight of projectile thrown horizontally with speed $50 ms^{^{-1}}$ from a long inclined plane which makes an angle of $\theta = 45^o$ from horizontal  ........ $\sec$

The equation of motion of a projectile is $y = Ax -Bx^2$ where $A$ and $B$ are the constants of motion. The horizontal range of the projectile is

A projectile is projected from ground with initial velocity $\vec u\, = \,{u_0}\hat i\, + \,{v_0}\hat j\,$. If acceleration due to gravity $(g)$  is along the negative $y-$ direction then find maximum displacement in $x-$ direction